设Sn是等差数列{an}的前n项和,且S9-S4=40,则S13的值为( )
A.52
B.104
C.112
D.208
由题意可得:S9-S4=a5+a6+a7+a8+a9=40,
由等差数列的性质可得5a7=40,解得a7=8,
而S13=
=13(a1+a13) 2
=13a7=10413×2a7 2
故选B
设Sn是等差数列{an}的前n项和,且S9-S4=40,则S13的值为( )
A.52
B.104
C.112
D.208
由题意可得:S9-S4=a5+a6+a7+a8+a9=40,
由等差数列的性质可得5a7=40,解得a7=8,
而S13=
=13(a1+a13) 2
=13a7=10413×2a7 2
故选B