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问题 填空题
函数y=
1-2x
（x∈R）的值域是______．
答案

∵2x＞0，y=

1-2x
，

∴0≤1-2x＜1，

∴0≤y=

1-2x
＜1，

故函数y=

1-2x
（x∈R）的值域是{y|0≤y＜1}．

故答案为：{y|0≤y＜1}．

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