问题
解答题
计算: (1)(-1)3-
(2)2(4a2b-3ab)-(-5a2b+2ab) |
答案
(1)原式=-1-
×(-5)1 3
=-1+5 3
=
;2 3
(2)原式=8a2b-6ab+5a2b-2ab
=13a2b-8ab.
计算: (1)(-1)3-
(2)2(4a2b-3ab)-(-5a2b+2ab) |
(1)原式=-1-
×(-5)1 3
=-1+5 3
=
;2 3
(2)原式=8a2b-6ab+5a2b-2ab
=13a2b-8ab.