问题
解答题
(1)计算:
(2)化简:3(3x2y-xy2)-[2(x2y-5xy2)-x2y] (3)解方程:1-2(x-2)=3x-7 (4)解方程:
|
答案
(1)
×(-3)2-2 7
×6+10÷(-2 7
)7 2
=
×9-2 7
×6+10×(-2 7
)2 7
=
×(9-6-10)2 7
=
×(-7)2 7
=-2;
(2)3(3x2y-xy2)-[2(x2y-5xy2)-x2y]
=9x2y-3xy2-(2x2y-10xy2-x2y)
=9x2y-3xy2-2x2y+10xy2+x2y
=(9-2+1)x2y+(-3+10)xy2
=8x2y+7xy2;
(3)去括号得,1-2x+4=3x-7,
移项得,-2x-3x=-7-1-4,
合并同类项得,-5x=-12,
系数化为1得,x=
;12 5
(4)去分母得,3(1-x)=2(4x-1)-6,
去括号得,3-3x=8x-2-6,
移项得,-3x-8x=-2-6-3,
合并同类项得,-11x=-11,
系数化为1得,x=1.