问题
选择题
数列1
|
答案
由题意可得Sn=(1+
)+(3+1 2
)+(5+1 4
)+…+(2n-1+1 8
)1 2n
=(1+3+5+…+2n-1)+(
+1 2
+1 4
+…+1 8
)1 2n
=
+n(1+2n-1) 2
=n2+1-
(1-1 2
)1 2n 1- 1 2 1 2n
故选A
数列1
|
由题意可得Sn=(1+
)+(3+1 2
)+(5+1 4
)+…+(2n-1+1 8
)1 2n
=(1+3+5+…+2n-1)+(
+1 2
+1 4
+…+1 8
)1 2n
=
+n(1+2n-1) 2
=n2+1-
(1-1 2
)1 2n 1- 1 2 1 2n
故选A