问题 解答题
计算
(1)
(2-e)2
-
3e
9
2
e-
3
2
+(2
7
9
)-0.5-
3
5
π0

(2)log318-log32-log29•log34+2log23
答案

(1)原式=|2-e|-

3e
9
2
-
3
2
+[(
5
3
)2]-
1
2
-
3
5

=e-2-

3e3
+(
5
3
)-1-
3
5

=e-2-e+

3
5
-
3
5

=-2.

(2)原式=log3

18
2
-
2lg3
lg2
×
2lg2
lg3
+3

=log332-4+3

=2-4+3

=1.

判断题
判断题