问题
解答题
计算 (1)
(2)log318-log32-log29•log34+2log23. |
答案
(1)原式=|2-e|-
3 | e
| ||||
5 |
3 |
1 |
2 |
3 |
5 |
=e-2-
3 | e3 |
5 |
3 |
3 |
5 |
=e-2-e+
3 |
5 |
3 |
5 |
=-2.
(2)原式=log3
18 |
2 |
2lg3 |
lg2 |
2lg2 |
lg3 |
=log332-4+3
=2-4+3
=1.
计算 (1)
(2)log318-log32-log29•log34+2log23. |
(1)原式=|2-e|-
3 | e
| ||||
5 |
3 |
1 |
2 |
3 |
5 |
=e-2-
3 | e3 |
5 |
3 |
3 |
5 |
=e-2-e+
3 |
5 |
3 |
5 |
=-2.
(2)原式=log3
18 |
2 |
2lg3 |
lg2 |
2lg2 |
lg3 |
=log332-4+3
=2-4+3
=1.