问题 解答题
化简或求值:(1)lg8+lg125-log0.5
1
4
+3log32

(2)
a3
3a
(a
1
2
)
4
a-
1
3
(a>0)
答案

(1)lg8+lg125-log0.5

1
4
+3log32

=lg(8×125)-2+2

=lg1000=3.

(2)

a3
3a
(a
1
2
)
4
a-
1
3
(a>0)

=

a
3
2
a
1
6
a2a-
1
3

=a

3
2
+
1
6
-2+
1
3

=a0

=1.

单项选择题
单项选择题 A1/A2型题