问题 解答题
(1)计算(
3
2
)-
1
3
×(-π)0+8
1
4
×
42
+(
32
×
3
)6-
(
2
3
)
2
3

(2)已知log189=a,18b=5,求log365.
答案

(1)(

3
2
)-
1
3
×(-π)0+8
1
4
×
42
+(
32
×
3
)6-
(
2
3
)
2
3

=(

2
3
)
1
3
+2
3
4
×2
1
4
+22×33-(
2
3
)
1
3

=2+4×27

=110.

(2)∵log189=a,

a=log18

18
2
=1-log182,

又∵18b=5,

∴b=log185,

log365=

log185
log1836
=
log185
1+log182
=
b
2-a

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