问题
解答题
(1)计算(
(2)已知log189=a,18b=5,求log365. |
答案
(1)(
)-3 2
×(-π)0+81 3
×1 4
+(4 2
×3 2
)6-3 (
)2 3 2 3
=(
)2 3
+21 3
×23 4
+22×33-(1 4
)2 3 1 3
=2+4×27
=110.
(2)∵log189=a,
∴a=log18
=1-log182,18 2
又∵18b=5,
∴b=log185,
∴log365=
=log185 log1836
=log185 1+log182
.b 2-a