问题 解答题
计算:(1)log2[log3(log5125)]
(2)(2a
2
3
b
1
2
)(-6a
1
2
b
1
3
)÷(-3a
1
6
b
5
6
)

(3)log3
427
3
+lg25+lg4+7log72
答案

(1)原式=log2(log33)=log21=0

(2)原式=[2×(-6)÷(-3)]a

2
3
+
1
2
-
1
6
b
1
2
+
1
3
-
5
6
=4a

(3)原式=log3 

3
3
4
3
 +lg(25×4)+2=log33-
1
4
+lg102+2

=-

1
4
+2+2=
15
4

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