已知函数f(x)满足:对任意实数x1<x2,有f(x1)>f(x2),且f(x1-x2)=
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∵对任意实数x1<x2,有f(x1)>f(x2),∴f(x)是R上的减函数.
∵f(x1-x2)=
f(x1) |
f(x2) |
1 |
2 |
验证:f(x1-x2)=(
1 |
2 |
(
| ||
(
|
f(x1) |
f(x2) |
故答案为:(
1 |
2 |
已知函数f(x)满足:对任意实数x1<x2,有f(x1)>f(x2),且f(x1-x2)=
|
∵对任意实数x1<x2,有f(x1)>f(x2),∴f(x)是R上的减函数.
∵f(x1-x2)=
f(x1) |
f(x2) |
1 |
2 |
验证:f(x1-x2)=(
1 |
2 |
(
| ||
(
|
f(x1) |
f(x2) |
故答案为:(
1 |
2 |