问题 解答题
(1)设x=log32,求
33x-3-3x
3x-3-x
的值.
(2)已知log259=a,25b=8.用ab表示log5072.
答案

(1)∵x=log32,

∴3x=2,3-x=

1
2

33x-3-3x
3x-3-x
=
(3x-3-x)(32x+1+3-2x
3x-3-x

=32x+3-2x+1

=(3x+3-x2-1

=(2+

1
2
2-1

=

21
4

(2)∵log259=a,25b=8,

∴log5072=

log2572
log2550

=

log258+log259
1+log252

=

a+b
1+
b
3

=

3a+3b
b+3

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