问题
解答题
(1)设x=log32,求
(2)已知log259=a,25b=8.用ab表示log5072. |
答案
(1)∵x=log32,
∴3x=2,3-x=
,1 2
∴
=33x-3-3x 3x-3-x (3x-3-x)(32x+1+3-2x) 3x-3-x
=32x+3-2x+1
=(3x+3-x)2-1
=(2+
)2-11 2
=
.21 4
(2)∵log259=a,25b=8,
∴log5072=log2572 log2550
=log258+log259 1+log252
=a+b 1+ b 3
=
.3a+3b b+3