问题
解答题
求值或估算: (1)2log32-log3
(2)若lg6≈0.7782,求102.7782. |
答案
(1)原式=log322-log3
+log38=log332 9
=log39=2;4×8 32 9
(2)令102.7782=m,则lgm=2.778≈2+lg6=lg600,
故102.7782约为600.
求值或估算: (1)2log32-log3
(2)若lg6≈0.7782,求102.7782. |
(1)原式=log322-log3
+log38=log332 9
=log39=2;4×8 32 9
(2)令102.7782=m,则lgm=2.778≈2+lg6=lg600,
故102.7782约为600.