问题
填空题
圆C:ρ=4Sinθ的圆心C到直线l:
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答案
由圆C:ρ=4Sinθ得ρ2=4ρsinθ,化为x2+y2=4y,即x2+(y-2)2=4,∴圆心C(0,2),半径r=2.
把直线l:
(t为参数)的参数t消去得x+y=6.x=3+t y=3-t
∴圆心C(0,2)到直线l的距离d=
=2|0+2-6| 2
.2
故答案为2
.2
圆C:ρ=4Sinθ的圆心C到直线l:
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由圆C:ρ=4Sinθ得ρ2=4ρsinθ,化为x2+y2=4y,即x2+(y-2)2=4,∴圆心C(0,2),半径r=2.
把直线l:
(t为参数)的参数t消去得x+y=6.x=3+t y=3-t
∴圆心C(0,2)到直线l的距离d=
=2|0+2-6| 2
.2
故答案为2
.2
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