问题
解答题
计算: (1)[2-5×(-
(2)-24+(3-7)2-2×(-1)2 (3)3x2y-4xy2-3+5x2y+2xy2+5 (4)3(2x2-y2)-2(3y2-2x2). |
答案
(1)原式=(2-
)÷(-5 4
)=1 4
×(-4)=-3;3 4
(2)原式=-16+16-2=-2;
(3)原式=8x2y-2xy2+2;
(4)原式=6x2-3y2-6y2+4x2=10x2-9y2;