问题 解答题
计算:
(1)
1
2
-
3
4
+(-
1
6
)

(2)(1
3
4
-
1
3
-2
1
6
)×24;
(3)-
1
9
×(-6
1
4
)×5.4÷(-0.125)

(4)(-2)4-[-32-(1-23)×7];
(5)2x+3y-4(y-x);
(6)a2b-[2(a2b-2ac2)-(2bc-4ac2)].
答案

(1)原式=

1
2
-
3
4
-
1
6

=

6
12
-
9
12
-
2
12

=-

5
12

(2)原式=

7
4
×24-
1
3
×24-
13
6
×24

=42-8-52

=-18;

(3)原式=-

1
9
×(-
25
4
)×
27
5
×(-8)

=-30;

(4)原式=16-[-9-(-7)×7]

=16-[-9+49)

=16-40

=-24;

(5)原式=2x+3y-4y+4x

=6x-y;

(6)原式=a2b-[2a2b-4ac2-2bc+4ac2]

=a2b-2a2b+4ac2+2bc-4ac2

=-a2b+2bc.

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