问题
解答题
化简: (1)
(2)
|
答案
(1)原式=
=a
b•[(ab2)3 2
]1 3 1 2 ab2•(
)b a 1 3
=aa
b•a3 2
b1 6 1 3 a
b2 3 7 3
+3 2
-1 6
b1+2 3
-1 3
=7 3
;a b
(2)原式=(
)25 4
-(1 2
)27 8
+(1 3
)625 10000
+(1 4
)64 1000
×(-2.5)×1 3
-π02 5
=
-5 2
+3 2
+(1 2
)-1-1=3.2 5