问题
填空题
(理)对于数列,若
|
答案
∵
[(3n-1)an]=1lim n→∞
∴
an=lim n→∞
=01 3n-1
∴
nan =lim n→∞
{lim n→∞
[3n-1)an+1 3
an]}=1 3 lim n→∞
[3n-1)an]+1 3 lim n→∞
an1 3
=1 3
故答案为:1 3
(理)对于数列,若
|
∵
[(3n-1)an]=1lim n→∞
∴
an=lim n→∞
=01 3n-1
∴
nan =lim n→∞
{lim n→∞
[3n-1)an+1 3
an]}=1 3 lim n→∞
[3n-1)an]+1 3 lim n→∞
an1 3
=1 3
故答案为:1 3