A，B两物体x-t图象如图所示，由图可知（）
A．在5s内两物体的位移相同，5s末两物体相遇
B．从第3s起，两物体运动方向相同，且vA>vB
C．两物体由同一位置开始运动，但是物体A比B迟3s才开始运动
D．5s内两物体的平均速度相等
参考答案：B
解析：
A物体5s内的位移为10m，B物体5s内的位移为5m，位移不相同，但5s末两者相遇，A错误；A物体在3s末开始运动，和B物体运动方向一致，图像的斜率表示运动速度，所以有vA>vB，B正确；A开始的初位置在坐标原点，B在x=5m处出发，C错误，A物体的平均速度为2m/s，B物体的平均速度为5m/s，平均速度不同，D错误
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