问题
解答题
计算题 (1)-40-28-(-19)+(-24) (2)(
(3)(-3)×
(4)(-1)100-
(5)a+(4a-3b)-(a-2b) (6)( 5a2+2b2)-3(a2-4b2) |
答案
(1)原式=-40-28+19-24
=-92+19
=-73;
(2)原式=-60×
+60×2 3
+60×1 12 1 15
=-40+5+4
=-31;
(3)原式=-3×
×(-1 3
)×(-1 2
)1 2
=-
;1 4
(4)原式=1-
×(3-9)1 6
=1-
×(-6)1 6
=1+1
=2;
(5)原式=a+4a-3b-a+2b
=4a-b;
(6)原式=5a2+2b2-3a2+12b2
=2a2+14b2.