问题 解答题
(1)计算:log23•log34+lg4+lg25
(2)化简:
m
3m
4m
(
6m
)5m
1
4
(m>0)
答案

(1)log23•log34+lg4+lg25

=

lg3
lg2
lg4
lg3
+2lg2+2lg5

=

lg4
lg2
+2(lg2+lg5)

=

2lg2
lg2
+2lg10=2+2=4;

(2)

m
3m
4m
(
6m
)5m
1
4

=

m
1
2
m
1
3
m
1
4
m
5
6
m
1
4

=

m
1
2
+
1
3
+
1
4
m
5
6
+
1
4

=

m
13
12
m
13
12
=1.

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