问题 解答题
求下列各式的值:
(1)
a-4b2
3ab2
(a>0,b>0)

(2)log2
7
48
+log212-
1
2
log242-1

(3)
1+
1
2
lg9-lg240
1-
2
3
lg27+lg
36
5
+1

(4)0.027-
1
3
-(-
1
6
)-2+2560.75+(
1
3
-1
)0-3-1
答案

(1)∵a>0,b>0,∴

a-4b2
3ab2
=
b
a2
6ab2
 

=a-2•b•a

1
6
b
1
3
=a-
11
6
b
4
3
.…(3分)   

(2)log2

7
48
+log212-
1
2
log242-1=log2
12
7
48
42
-1=log2(
12
24
2
)
-1

=log2

2
- log22-1=
1
2
-1-1=-
3
2
.…(3分)

(3)

1+
1
2
lg9-lg240
1-
2
3
lg27+lg
36
5
+1=
1+lg3-lg240
1-lg9+lg
36
5
+1
=
lg
30
240
lg(
10
9
• 
36
5
)
=
lg
1
8
lg8
=-1.  …(3分)        

 (4)0.027-

1
3
-(-
1
6
)
-2
+2560.75+(
1
3
-1
)
0
-3-1=0.3-1-36+43+1-
1
3
 

=

10
3
-36+64+1-
1
3
=32.…(3分)

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