问题
解答题
计算: (1)23-(+18)-(-7)+(-12); (2)(
(3)16÷(-2)-(-
(4)-(-
(5)(x+y-z)+(x-y+z)-(x-y-z) (6)-2y3+(3xy2-x2y)-2(xy2-y3) |
答案
(1)原式=23-18+7-12=30-30=0;
(2)原式=(-36)×
-(-36)×7 9
+(-36)×5 6
=-28+30-27=-25;3 4
(3)原式=-8+2=-6;
(4)原式=-
×4-3÷(-4)×1 4
=-1+1 4
=-3 16
;13 16
(5)原式=x+y-z+x-y+z-x+y+z=x+y+z;
(6)原式=-2y3+3xy2-x2y-2xy2+2y3=xy2-x2y.