问题
填空题
计算: (1)2
(2)log3
|
答案
(1)原式=2× 3
×121 2
×(1 6
)3 2
=2×31 3
×31 2
×21 6
×31 3
×2-1 3
=21+1 3
-1 3
×31 3
+1 2
+1 6
= 2×3=61 3
(2)原式=log33-4+lg
+lg4+2=-4-lg4+lg4+2=-21 4
计算: (1)2
(2)log3
|
(1)原式=2× 3
×121 2
×(1 6
)3 2
=2×31 3
×31 2
×21 6
×31 3
×2-1 3
=21+1 3
-1 3
×31 3
+1 2
+1 6
= 2×3=61 3
(2)原式=log33-4+lg
+lg4+2=-4-lg4+lg4+2=-21 4