问题 填空题
化简:(1)(
1
4
)-
1
2
(
4ab-1
)
3
(0.1)-2(a3b-3)
1
2
=______.(a>0,b>0)
(2)(
32
×
3
)6+(
2
2
)
4
3
-4(
16
49
)-
1
2
-
42
×80.25-(-2005)0
=______.
答案

(1)(

1
4
)-
1
2
(
4ab-1
)
3
(0.1)-2(a3b-3)
1
2

=2×

23a
3
2
b-
3
2
 
100a
3
2
b-
3
2

=

4
25

(2)(

32
×
3
)6+(
2
2
)
4
3
-4(
16
49
)-
1
2
-
42
×80.25-(-2005)0

=(2

1
3
3
1
2
6+(2
1
2
2
1
4
4
3
-4×
7
4
-2
1
4
× 8
1
4
-1

=4×27+2-7-2-1

=100

故答案为:

4
25
,100

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