问题
填空题
已知a,b为正常数,化简(2a
|
答案
(2a
b2 3
)•(-6a1 2
b1 2
)÷(3a1 3
b1 6
)=[2×(-6)÷3]a5 6
+2 3
-1 2
b1 6
+1 2
-1 3
=-4a1b0=-4a.5 6
故答案为:-4a.
已知a,b为正常数,化简(2a
|
(2a
b2 3
)•(-6a1 2
b1 2
)÷(3a1 3
b1 6
)=[2×(-6)÷3]a5 6
+2 3
-1 2
b1 6
+1 2
-1 3
=-4a1b0=-4a.5 6
故答案为:-4a.