问题
解答题
计算: (1)(-3)2-
(2)[(1-
|
答案
(1)原式=9-
×(3×3 5
-1)+8×(4 9
+1 4
-1)1 8
=9-
×3 5
+2+1-81 3
=4-1 5
=3
;4 5
(2)原式=[(
)2-2 3
×5 3
]×(-8 9
)33 2
=(
-4 9
)×(-40 27
)27 8
=
×(-4 9
)-27 8
×(-40 27
)27 8
=-
+53 2
=3
.1 2