问题 填空题
计算
3a4
-8
3a
b
3a2
+2
3ab
+4
3b2
÷(1-2
3
b
a
)
=______.
答案

3a4
-8
3a
b
3a2
+2
3ab
+4
3b4
÷(1-2
3
b
a
)

=(

a
4
3
-8(ab3)
1
3
a
2
3
+2(ab)
1
3
+4b
4
3
)÷(1-2(
b
a
)
1
3
)

=

a
1
3
×(a-8b)
(a
2
3
+2a
1
3
b
1
3
+4b
2
3
×
a
1
3
a
1
3
- 2b
1
3

=

a
2
3
×(a-8b )
a-8b 

=a

2
3

故答案为:a

2
3

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