问题
解答题
(1)4x
(2) 求值:lg5+lg2-(-
|
答案
(1)4x
(-3x1 4
y-1 4
)÷(-6x-1 3
y-1 2
)=(-12x2 3
+1 4
y-1 4
)÷(-6x-1 3
y-1 2
)2 3
=2x
+1 2
y-1 2
+1 3
=2xy2 3
,1 3
(2)lg5+lg2-(-
)-2+(1 3
-1)0+log282
=lg10-32+1+3log22=-4