问题 解答题
(1)loga2+loga
1
2
(a>0且a≠1);
(2)lg20+log10025;
(3)2
3
×
612
×
3
3
2
答案

(1)loga2+loga

1
2
=loga2-loga2=0

(2)lg20+log10025=lg2+1+

lg25
2
=lg2+1+lg5=2

(3)2

3
×
612
×
3
3
2
=2×3
1
2
×12
1
6
×(
3
2
)
1
3
=21+
2
6
-
1
3
×3
1
2
+
1
6
+
1
3
=2×3=6

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