问题
解答题
计算(1)(lg2)2+lg5•lg20-1+2log525+3log264-8ln1 (2)(
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答案
(1)原式=(lg2)2+(1-lg2)(1+lg2)-1+2×2+3log226-0
=(lg2)2+1-(lg2)2-1+4+18=22
(2)原式=(2
×31 3
)6+(21 2
×21 2
)1 4
-4×4 3
-27 4
×21 4
-13 4
=22×33+2-7-2-1=100