问题 解答题
计算下列各式的值:
(1)(
32
×
3
)6+(
2
)
4
3
-(-2008)0
; 
(2)lg5lg20+(lg2)2
答案

(1)原式=(2

1
3
×3
1
2
)6+(2×2
1
2
)
1
2
×
4
3
-1

=2

1
3
×6×3
1
2
×6
+2
3
2
×
1
2
×
4
3
-1

=22×33+2-1=109

(2)原式=lg5lg(5×4)+(lg2)2=lg5(lg5+lg4)+(lg2)2

=(lg5)2+lg5lg4+(lg2)2

=(lg5)2+2lg5lg2+(lg2)2

=(lg5+lg2)2

=1

单项选择题
填空题