问题
解答题
计算题: (1)9+(-10)+(-2)-(-3); (2)(
(3)(-10)2+[(-5)2-(3+22)×2]. |
答案
(1)原式=9-10-2+3=0;
(2)原式=(
×16-3 4
×16-1 6
×16)×(-3)1 12
=(12-
-16 6
)×(-3)4 3
=-36+8+4
=-24;
(3)原式=100+(25-7×2)=100+11=111.
计算题: (1)9+(-10)+(-2)-(-3); (2)(
(3)(-10)2+[(-5)2-(3+22)×2]. |
(1)原式=9-10-2+3=0;
(2)原式=(
×16-3 4
×16-1 6
×16)×(-3)1 12
=(12-
-16 6
)×(-3)4 3
=-36+8+4
=-24;
(3)原式=100+(25-7×2)=100+11=111.