问题
解答题
计算: (1)(2
(2)lg2+lg5+log2.56.25+lg
|
答案
(1)(2
)0+2-2×(3 5
)-1-1001 4
=1+1 2
×4-1 22
=2-10=-8.100
(2)lg2+lg5+log2.56.25+lg
+ln1 100
=lg10+e
+lg10-2+lnelg(2.5)2 lg2.5
=1+2-2+1 2
=1 2
.3 2
计算: (1)(2
(2)lg2+lg5+log2.56.25+lg
|
(1)(2
)0+2-2×(3 5
)-1-1001 4
=1+1 2
×4-1 22
=2-10=-8.100
(2)lg2+lg5+log2.56.25+lg
+ln1 100
=lg10+e
+lg10-2+lnelg(2.5)2 lg2.5
=1+2-2+1 2
=1 2
.3 2