问题 解答题
计算:
(1)lg22+lg5•lg20-1;
(2)(
32
3
)6-4(
16
49
)-
1
2
-
42
80.25-(-2013)0
答案

(1)lg22+lg5•lg20-1

=lg22+(1-lg2)(1+lg2)-1

=lg22+1-lg22-1=0;

(2)(

32
3
)6-4(
16
49
)-
1
2
-
42
80.25-(-2013)0

=(2

1
3
3
1
2
)6-4[(
7
4
)-2]-
1
2
-2
1
4
•(23)
1
4
-1

=2

1
3
×6•3
1
2
×6
-4×
7
4
-2
1
4
2
1
4
-1

=22•33-7-2-1=98.

名词解释
单项选择题