问题
解答题
计算: (1)lg22+lg5•lg20-1; (2)(
|
答案
(1)lg22+lg5•lg20-1
=lg22+(1-lg2)(1+lg2)-1
=lg22+1-lg22-1=0;
(2)(
•3 2
)6-4(3
)-16 49
-1 2
•80.25-(-2013)04 2
=(2
•31 3
)6-4[(1 2
)-2]-7 4
-21 2
•(23)1 4
-11 4
=2
×6•31 3
×6-4×1 2
-27 4
•23×1 4
-11 4
=22•33-7-2-1=98.