问题
解答题
(重点班做)计算下列各式的值: (1)(0.0081)-
(2)2(lg
|
答案
(1)原式=(
)-34 104
-(3)-1×[(34)-1 4
+(1 4
)-33 23
]-1 3
-10×(1 2
)33 103
=1 3
-10 3
-3=01 3
(2)原式=2(
lg2)2+1 2
lg2•lg5+1 2 (
lg2)2-lg2+11 2
=
(lg2)2+1 2
lg2•lg5+1 2 (
lg2-1)21 2
=
(lg2)2+1 2
lg2•lg5+1-1 2
lg21 2
=
lg2(lg2+lg5)+1-1 2
lg21 2
=1.