问题 解答题
(重点班做)计算下列各式的值:
(1)(0.0081)-
1
4
-[3×(
7
8
)0]-1×[81-0.25+(3
3
8
)-
1
3
]-
1
2
-10×0.027
1
3

(2)2(lg
2
)2+lg
2
•lg5+
(lg
2
)
2
-lg2+1
答案

(1)原式=(

34
104
)-
1
4
-(3)-1×[(34)-
1
4
+(
33
23
)
-
1
3
]
-
1
2
-10×(
33
103
)
1
3
=
10
3
-
1
3
-3=0

(2)原式=2(

1
2
lg2)2+
1
2
lg2•lg5+
(
1
2
lg2)
2
-lg2+1

=

1
2
(lg2)2+
1
2
lg2•lg5+
(
1
2
lg2-1)
2

=

1
2
(lg2)2+
1
2
lg2•lg5+1-
1
2
lg2

=

1
2
lg2(lg2+lg5)+1-
1
2
lg2

=1.

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