问题 解答题
(1)计算:(0.0625)-
1
4
-[-2×(
7
3
)0]2×[(-2)3]
1
3
+10(2-
3
)-1-(
1
300
)-0.5

(2)计算:
lg23-lg9+lg10
(lg
27
+lg8-lg
1000
)
(lg0.3)(lg1.2)
答案

(1)原式=(

1
2
)4×(-
1
4
)
-22×(-2)+
10(2+
3
)
(2-
3
)(2+
3
)
-
300

=2+8+10(2+

3
)-10
3
=30.

(2)原式=

lg⁡23-2lg⁡3+1
⋅(lg⁡
27
×8
1000
)
lg⁡
3
10
⋅lg⁡
12
10
=
(lg⁡3-1)2
⋅(
3
2
lg⁡3+3lg⁡2-
3
2
)
(lg⁡3-1)⋅(lg⁡3+2lg⁡2-1)

=

(1-lg⁡3)⋅
3
2
(lg⁡3+2lg⁡2-1)
(lg⁡3-1)⋅(lg⁡3+2lg⁡2-1)
=-
3
2

单项选择题
问答题 简答题