问题
解答题
计算 (1)(2
(2)2(lg
|
答案
(1)(2
)0.5+0.1-2+(27 9
)-10 27
-3π0+2 3 37 48
=(
)25 9
+(1 2
)-2+(1 10
)-64 27
-3+2 3 37 48
=
+100+5 3
-3+9 16 37 48
=100
(2)2(lg
)2+lg2
•lg5+2 (lg
)2-lg2+12
=2×
lg22+1 4
lg2lg5+|1-1 2
lg2|1 2 =
lg2(lg2+lg5)+1-1 2
lg21 2 =
lg2+1-1 2
lg21 2 =1