问题 解答题
计算
(1)(2
7
9
)0.5+0.1-2+(2
10
27
)-
2
3
-3π0+
37
48

(2)2(lg
2
)2+lg
2
•lg5+
(lg
2
)
2
-lg2+1
答案

(1)(2

7
9
)0.5+0.1-2+(2
10
27
)-
2
3
-3π0+
37
48

=(

25
9
)
1
2
+(
1
10
)-2+(
64
27
)-
2
3
-3+
37
48

=

5
3
+100+
9
16
-3+
37
48

=100

(2)2(lg

2
)2+lg
2
•lg5+
(lg
2
)
2
-lg2+1

=2×
1
4
lg22+
1
2
lg2lg5+|1-
1
2
lg2|
=
1
2
lg2(lg2+lg5)+1-
1
2
lg2
=
1
2
lg2+1-
1
2
lg2
=1

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