(

3	2

×

3

)6+(

2 2

)

4

3

-4(

16

49

)-

1

2

-

4	2

×80.25-(-2005)0

=（2

1

3

×3

1

2

）⁶+[(2×2

1

2

)

1

2

]

4

3

-4[(

4

7

)2]-

1

2

-2

1

4

×2

3

4

-1

=2²×3³+2-7-2-1

=100