问题 解答题
(1)化简:
a
1
3
(a-8b)
4b
2
3
+2a
1
3
b
1
3
+a
2
3
÷(1-
2b
1
3
a
1
3
)•a
1
3
+(π-1)0

(2)求值:(lg5)2+lg2•lg50+log2
1
25
•log3
1
8
•log5
1
9
答案

(1)

a
1
3
(a-8b)
4b
2
3
+2a
1
3
b
1
3
+a
2
3
÷(1-
2b
1
3
a
1
3
)•a
1
3
+(π-1)0

=

a
1
3
(a
1
3
-(2b)
1
3
) (4b
2
3
+2a
1
3
b
1
3
+a
2
3
)    
4b
2
3
+2a
1
3
b
1
3
+a
2
3
÷(
a
1
3
-2b
1
3
a
1
3
)•a
1
3
+1=a+1

(2)(lg5)2+lg2•lg50+log2

1
25
•log3
1
8
•log5
1
9

=(1-lg2)2+lg2(2-lg2)+

lg
1
25
lg2
lg
1
8
lg3
lg
1
9
lg5

=1+

2lg2-2
lg2
-3lg2
lg3
-2lg3
1-lg2

=1+(-2)×(-3)×(-2)

=-11

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