问题 解答题
求下列式子的值:
(1)(2
1
4
)
1
2
-(-2008.11)0-(
27
8
)-
2
3
+(1.5)-2

(2)(log43+log83)(log32+log92)
答案

(1)原式=[(

3
2
)2]
1
2
-1-[(
2
3
)-3]-
2
3
+(
3
2
)-2
=
3
2
-1-(
2
3
)2+(
2
3
)2
=
1
2

(2)原式=(

lg3
2lg2
+
lg3
3lg2
)(
lg2
lg3
+
lg2
2lg3
)
=(
1
2
+
1
3
)(1+
1
2
)
=
5
4

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