问题
解答题
求下列各式的值. (1)(
(2)已知x+x-1=3,求式子x2+x-2的值. |
答案
(1)(
)9 4
-(-9.6)0-(1 2
)27 8
+(2 3
)2+lg25+lg43 2
=
-1-[(3 2
)3]3 2
+(2 3
)2+lg1003 2
=
-(1 2
)2+(3 2
)2+2=3 2
;5 2
(2)由x+x-1=3,两边平方得x2+2+x-2=9,
所以x2+x-2=7.