问题
解答题
求下列式子的值. (1)-
(2)(-3)2÷2
|
答案
(1)-
×[(-4 5
)÷(0.75-1)+(-2)5]1 2
=-
×[(-4 5
)÷(1 2
-1)-32]3 4
=-
×[(-4 5
)÷(-1 2
)-32]1 4
=-
×[(-4 5
)×(-4)-32]1 2
=-
×[2+(-32)]4 5
=-
×(-30)4 5
=24;
(2)(-3)2÷2
×(-1 4
)2+4-22×(-2 3
)1 3
=9÷
×9 4
+4-4×(-4 9
)1 3
=9×
×4 9
+4+4 9 4 3
=
+16 9
+36 9 12 9
=
.64 9