问题 解答题
求下列式子的值.
(1)-
4
5
×[(-
1
2
)÷(0.75-1)+(-2)5]

(2)(-3)2÷2
1
4
×(-
2
3
)2+4-22×(-
1
3
)
答案

(1)-

4
5
×[(-
1
2
)÷(0.75-1)+(-2)5]

=-

4
5
×[(-
1
2
)÷(
3
4
-1)-32]

=-

4
5
×[(-
1
2
)÷(-
1
4
)-32]

=-

4
5
×[(-
1
2
)×(-4)-32]

=-

4
5
×[2+(-32)]

=-

4
5
×(-30)

=24;

(2)(-3)2÷2

1
4
×(-
2
3
)
2
+4-22×(-
1
3
)

=9÷

9
4
×
4
9
+4-4×(-
1
3

=9×

4
9
×
4
9
+4+
4
3

=

16
9
+
36
9
+
12
9

=

64
9

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