问题 解答题
化简:
(1)
6
1
4
-(π-1)0-(3
1
8
)
1
3
-(
1
64
)-
2
3

(2)lg2•lg50+lg25-lg5•lg20.
答案

(1)

6
1
4
-(π-1)0-(3
1
8
)
1
3
-(
1
64
)-
2
3

=

5
2
-1-
3
2
-(
1
4
-2

=-16.

(2)lg2•lg50+lg25-lg5•lg20

=lg2(1+lg5)+2lg5-lg5(2lg2+lg5)

=lg2+lg2lg5+2lg5-2lg2lg5-(lg5)2

=lg2+2lg5-lg5(lg2+lg5)

=lg2+lg5

=1.

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