问题
解答题
计算: (1)(2
(2)lg14-21g
|
答案
(1)(2
)0+2-2×(23 5
)-1 4
-(0.01)0.51 2
=1+
×1 4
-0.12 3
=1+
-1 6 1 10
=
.16 15
(2)lg14-21g
+lg7-lg187 3
=lg(14÷
×7÷18)49 9
=lg1
=0.
计算: (1)(2
(2)lg14-21g
|
(1)(2
)0+2-2×(23 5
)-1 4
-(0.01)0.51 2
=1+
×1 4
-0.12 3
=1+
-1 6 1 10
=
.16 15
(2)lg14-21g
+lg7-lg187 3
=lg(14÷
×7÷18)49 9
=lg1
=0.