问题 解答题
(1)计算
lg2+lg5-lg8
lg50-lg40

(2)已知x
1
2
+x-
1
2
=3
,求
x
3
2
+x-
3
2
+2
x2+x-2+3
的值.
答案

(1)

lg2+lg5-lg8
lg50-lg40
=
1-3lg2
lg
5
4
=
1-3lg2
lg
10
8
=
1-3lg2
1-3lg2
=1

(2)

x
3
2
+x-
3
2
+2
x2+x-2+3
=
(x
1
2
+x-
1
2
)×(x-1+
1
x
)+2
(x+
1
x
)
2
+1
=
3×[′(x 
1
2
+x -
1
2
) 2-3]+2  
10
=
20
10
=2

多项选择题
单项选择题