将基因型为AABBCC和AaBbCc的向日葵杂交,按基因自由组合规律,后代中基因型为AABBCC的个体比例应为:[ ]
A.1/8
B.1/16
C.1/32
D.1/64
答案:A
--- Did you go to the cinema to see 3D The Hobbit last night?
--- No, I ________ go to the cinema. The tickets are too expensive.
A.hardly
B.nearly
C.still
D.only
在窗体上画一个名称为Commandl的命令按钮,然后编写如下事件过程: Private Sub Command1_Click()y = 8Print fun1(1 + fun1(fun1(fun1(y)))*10) End Sub Private FLinctiOn fUnl(a)funl(a) = 1 + a End Function 程序运行后,单击命令按钮,则窗体上显示的内容是
A.112
B.2
C.909090
D.1001