问题
解答题
求未知数x. (1)0.4:0.25=
(2)0.6x+
|
答案
(1)0.4:0.25=
,12 x
0.4x=0.25×12,
0.4x÷0.4=3÷0.4,
x=7.5;
(2)0.6x+
x-0.2=11 10
,1 5
x-0.2=17 10
,1 5
x-0.2+0.2=17 10
+0.2,1 5
x÷7 10
=7 10
÷7 5
,7 10
x=2.