问题
选择题
给定四条曲线:①x2+y2=
|
答案
①中,圆心(0,0)到直线x+y-
=0的距离为5
等于半径,故满足题意.5 2
②中,联立方程
,整理得,13x2-18
+x2 9
=1y2 4 x+y-
=05
x+9=0.△≠0,故不满足题意.5
③中,联立方程
.整理得,5x2-2x2+
=1y2 4 x+y-
=05
x+1=0.△=0,故满足题意.5
④中,联立方程
,整理得,5x2-8
+y2=1x2 4 x+y-
=05
x+16=0,△=0.故满足题意.5
故本题中①③④满足,答案为D.