()以一定时期的累计责任赔付率为基础计算责任限额。
A.超额赔款分保
B.事故超赔分保
C.超额损失分保
D.超额赔付率分保
参考答案:D
化简求值:(2x2y﹣4xy2)﹣(﹣3xy2+x2y),其中x=﹣1,y=2.
在学生选课表(SC)中,查询选修了3号课程(课程号CH)的学生的学号(XH)及其成绩(GD)。查询结果按分数的降序排列。实现该功能的正确SQL语句______。
A.SELECT XH, GD FROM SC WHERE CH='3' ORDER BY GD DESC;
B.SELECT XH, GD FROM SC WHERE CH='3' ORDER BY GD ASC;
C.SELECT XH, GD FROM SC WHERE CH='3' GROUP BY GD DESC;
D.SELECT XH, GD FROM SC WHERE CH='3' GROUP BY GD ASC;