下图为我国东部某地区等高线地形图，读图完成下列各题。
图中山峰与桥梁A的相对高度最有可能是（）
A．450米
B．650米
C．750米
D．850米
参考答案：B
解析：根据图例中的海拔高度表，可以判断山顶的海拔高度约900-1000米，桥梁A的海拔高度约300-400米，然后计算出两地的高差范围是大于500米，小于700米，所以只有B对。A、C、D错。也可以根据图例，判断出等高距是100米，两地之间有6条等高线，然后根据高差公式计算。结果相同。
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